There has been enough usage on this blog to make another post appropriate, if only to be more convenient for you, the student.
Please comment to this post now.
Thanks,
Barry
Subscribe to:
Post Comments (Atom)
Subscribe to this blog!
Posts
Comments
About Me
- Barry Edwards
- This blog is a place for students to ask me questions while I am not available on campus. I receive notification of a student question as soon as it is posted. Please take advantage of this blog for such math questions.
Hi Barry,
ReplyDeleteI'm in your MHCC Math 111 class, and unfortunately I'm not having a good time with figuring out the parallel and perpendicular equations such as question on the HW Chapter 1, Section 1.5 Question 17ab
Remember that "parallel" means the slopes are the same. so on part a, use the slope of line L and the given point to find the equation.
ReplyDeleteAlso, recall "perpendicular" means the slopes are negative reciprocals. If the slope of line L is 8/9, the slope of the perpendicular line is -9/8 ("flip it over, change the sign"). Now use the new slope and the given point to find your equation.
Barry
I'm in your mth243 class. My question is about 3d on assignment 2 (Problem set: probability). What is the probability of not being a freshmen or being an upperclassman? Is it asking about them at the same time, both not being freshman or upperclassman (only leaving sophomore) or the percentage of them each separately but averaged together? The answer on the answer sheet only answers the first part of the question (not being a freshmen, which is 0.58).
ReplyDelete^ nevermind, I figured it out. :)
ReplyDeleteI'm in your 243 class. In the Probability homework set, 6c,d are stumping me. When you are using the "Rules" Addition, Conditional, etc. how do you set up the numbers to get the appropriate answer?
ReplyDeleteI'll have to show you that one in class.
ReplyDeleteBarry
Hey Barry,
ReplyDeleteMy name's Levi. I'm a tutor upstairs in the learning success center, and once again I'm finding myself get stumped on the lottery problem on page 24 of your Stat 243 book, #10:
Assuming there are 52 possible numbers in a lottery, what is the chance you choose only one correct lottery number out of six winning numbers? Note that the "one correct number" can be in any of the six positions.
The only interpretation I've come up with for the problem that comes anywhere close is to think of a sequence of 6 balls, picked from a bin of 52 balls with the numbers 1 through 52 written on them. So we then want the probability:
P(W&L&L&L&L&L or L&W&L&L&L&L or L&L&W&L&L&L or L&L&L&W&L&L or L&L&L&L&W&L or L&L&L&L&L&W)
Which I wrote out by hand(using conditional probability for the "and" statements) and got .411. Anyway, it's not quite what you have in the back of the book, and besides it just seems a little too complicated...am I close?
Levi,
ReplyDeleteThanks for your interest in my students and all you do to help them in the Learning Success Center.
On the problem ... choosing only one correct number out of six can occur no matter which position the correct number is in. But to make this easier, let's place the correct number in the first position ... for now.
Also note that there are 6 correct numbers and therefore 46 incorrect numbers in any lottery drawing.
So, lets use the Fundamental Counting Rule. There are 6 choices for the first number, 46 choices for the second number, 45 choices for the third number, and so forth (6x46x45x44x43x42=986,942,880 possible combinations).
And of course there are 52x51x50x49x48x47=1.466e10 possible lottery draws of 6 numbers.
So, P(first number only is correct) = 0.0673. However, the probability will be the same no matter which position we place the correct number. Hence, there are six viable positions with the same chance of occurring and P(only one correct number)= 6x0.0673 = 0.404, the answer in my supplement's answer pages.
Thanks Barry! Yes, that makes sense now. :)
ReplyDeleteLevi
Hi Barry,
ReplyDeleteI am in your Math 95 class at PCC. Last minute question on the quiz that keeps bugging me. I am pretty sure I figured out the "kool-aid" stand question except for one bit. Shall I assume that the $1.25 per week "supplies" cost is the number for me to work with? Does the "per week" mean that I should account for a monthly distribution instead? Examples from the book (like the purchasing of 500 blank CD's at $250) were unchanged and remained as that amount within the formula.
Thanks for any last minute help,
Melissa Pomeroy
Melissa,
ReplyDeleteYour accounting period is a week (it makes it simpler).
So, you have two costs: 1) $1.25 per week and 2) 13.5 cents ($0.135) per cup sold. Ask yourself two questions: 1) My fixed costs each week are what? and 2) My variable costs per week are?
The second cost includes your number of units sold.
Hope this helps,
Barry
Little Miss Jurie of mth 243 MHCC forgot to NOT press delete while editing data in L1. Oops! How do I get L1 back on TI 84? Thanks. Enjoy the snow.
ReplyDeletePress [STAT] then choose command 5:Set Up Editor.
ReplyDeleteAfter the command shows up on the home screen, press [ENTER].
The display should read "Done".
Now press [STAT] and 1. L1 should be back where it belongs.
Barry
Thanks Bery Much!! Jurie Lewis mth 243
ReplyDeleteHello Barry,
ReplyDeleteThis is Leah from your MTH 111 course at MHCC. I have been checking the wiley plus site for homework #8 and nothing is posted, just wanted to make sure I'm not missing something.
Thanks
Hi Leah and others.
ReplyDeleteYes, there is no homework #8 ... yet.
Stay tuned.
Barry
Hey Barry its Janelle,
ReplyDeleteI am having a really tuff time with the quiz I got a in the first problem and u checked it in class on Mon. and said it was right I think I got b not sure it if is correct but I need help with the rest I feel overwhelmed with it!!!
Barry,
ReplyDeleteI am from your Math243 class.
For the team project what should we do for question 2) the interval ratio variables?
Remember, interval ratio variables are the numerical ones. On the handout, the variables are the columns. Pick a number of variables equal to the number of team members. Do EDA on each variable, then continue using the handout instructions.
ReplyDeleteBarry -
ReplyDeleteHow do you set the xscl for histograms again?
Thanks.
Use Sturge's Rule to decide how many classes to have for your histogram. Then divide the range by this to get the class width. You might have to widen the range a bit to make the division work nicely. This result is what xScl should be.
ReplyDeleteHi Barry!
ReplyDeleteDO we have class today?!
Using a Histogram how do you tell if something is "mound-shaped"
ReplyDeleteHey Barry,
ReplyDeleteThis is Leah from your MTH 111 course at MHCC. I'm having trouble with problem #4 of the take home quiz. I have the formula: p(n)=r(n)-c(n)
p(n)=-0.35n^2+35.4n-6.8n+240, but when asked to simplify, I can only see to combine the n's. Is that all you are looking for? When I continued on with that, my answers seemed off... please help:)
Thanks so much!
I meant to say my formula is
ReplyDeletep(n)=-0.35n^2+28.6n-240
Leah
Yes, combine like terms.
ReplyDelete